关于对async await效率问题的深入思考

 function myPromise(flag) {
     return new Promise((resolve, reject) => {
         if (flag) {
             return resolve(flag)
         } else {
             return reject('error')
         }
     })
 }
 // 在p1的回调调用p2
 const p1 = myPromise(1)
 p1.then(v => {
     const p2 = myPromise(2)
     p2.then(v => {
         console.log(v)
     })
 })

 function myPromise(flag) {
     return new Promise((resolve, reject) => {
         if (flag) {
             return resolve(flag)
         } else {
             return reject('error')
         }
     })
 }
 let v
 const p1 = await myPromise(1)
 p1.then(val => { v = val }) 
 const p2 = await myPromise(v)
 p2.then(val => { v = val })
 const p3 = await myPromise(v)
 p3.then(val => { v = val })
 const p4 = await myPromise(v)
 p4.then(val => { v = val })
 const p5 = await myPromise(v)
 p5.then(val => { v = val })
 const p6 = await myPromise(v)
 p6.then(val => { v = val })
 const p7 =  myPromise(v)

 function getData(url) {
     return url
 }
 ​
 function postData(url) {
     console.log(url)
 }
 ​
 let data1 = await getData('/xxx') // 操作1 需要花费10s
 let data2 = await getData('/xxx') // 操作2 需要花费10s
 postData(data1 + '/xxx') // 操作3 需要花费20s
 postData(data2 + '/yyy') // 操作4 需要花费5s

 function getData(url) {
     return url
 }
 ​
 function postData(url) {
     console.log(url)
 }
 ​
 let data1 = await getData('/xxx') // 操作1 需要花费10s
 postData(data1 + '/xxx') // 操作4 需要花费20s
 let data2 = await getData('/xxx') // 操作2 需要花费10s
 postData(data2 + '/yyy') // 操作3 需要花费5s

function t5s() {
    return new Promise((resolve, reject) => {
        setTimeout(() => {
            resolve(1)
            console.log('5s')
        }, 5000);
    })
}
function t3s() {
    return new Promise((resolve, reject) => {
        setTimeout(() => {
            resolve(1)
            console.log('3s')
        }, 3000);
    })
}
function t2s() {
    return new Promise((resolve, reject) => {
        setTimeout(() => {
            resolve(1)
            console.log('2s')
        }, 2000);
    })
}
/* 
    这里应该是等待5s后返回第一个Promise并打印5s，然后再等待3s后返回第二个Promise并打印3s，
    最后再等待2s后返回第三个Promise并打印2s，总用时10s
*/
(async () => {
    await t5s()
    await t3s()
    await t2s()
})()
/*
    这里我的理解是3个操作会依次进入微任务池中依次执行，因此2s后打印2s，3s后打印3s，5s后打印5s，总用时5s
*/
(() => {
    t5s()
    t3s()
    t2s()
})()