python中lambda匿名函数详解

def sum_func(a, b, c): 
    return a + b + c 
 
sum_lambda = lambda a, b, c: a + b + c 
print(sum_func(1, 10, 100)) # 111 
print(sum_lambda(1, 10, 100)) # 111

#无参数 
lambda_a = lambda: 100 
print(lambda_a()) # 100
 
#一个参数 
lambda_b = lambda num: num * 10 
print(lambda_b(5)) # 50
 
#多个参数 
lambda_c = lambda a, b, c, d : a + b + c + d 
print(lambda_c(1,2,3,4)) # 10
 
#表达式分支 
lambda_d = lambda x: x if x % 2 == 0 else x + 1 
print(lambda_d(6)) # 6 
print(lambda_d(7)) # 8 

f = lambda x: x * x 
print(f) # <function <lambda> at 0x00000253B601B598> 
print(f(5)) # 25

def sub_func(a, b, func): 
    print('a =', a) 
    print('b =', b) 
    print('a - b =',func(a, b))
 
sub_func(100, 1, lambda a, b: a - b)
#a = 100 
#b = 1 
#a - b = 99

def func(a, b): 
    return lambda c: a + b + c
return_func = func(1, 10) 
print(return_func) # <function func.<locals>.<lambda> at 0x00000253B6472D90> 
print(return_func(100)) # 111