python与matlab一些常用函数互转问题

b"\xd0\x01n\x01\xb3\x1b\x07\x05\xee\x06\xcc\xfe\x84\x12\xab\x07~\x08p\x00\x92\x14u\x01\xe4\x12d\xfe9\x08\xb0\x1e\xa6\x02\xb1C?\x18#E\x12\x12\x13^v\x04w\x1d\xe8\x04\x9bf\x1a\x1c\x9b\x0b\xb0\x11\xae%#\x06\xbe\x1f^\x15s.\x92\x10k'`\x0b[ {\x03!\x00 \x1b\xdf(\xec#\xfcH=\x02\x1e\x11!\x07\xba\xedu \xa7\x0e\xdb\x0by\xfb\x91\x05H\x03\xcb\x08\x94\x04\xfd\x13n\xf8\x07\x06d\xfd\xaf\t{\x17\xda$y\x10"

import struct

def updack_data(data):
    # 十六进制字节流转十进制
    dec_data = []
    for i in range(0, len(data), 2):
        dec_data.append(struct.unpack("@h", data[i: i + 2])[0])  # 小端
    return dec_data

with open('data', 'rb') as f:
    signal = f.read()
    print(updack_data(signal))

import numpy as np
a = b"\xd0\x01n\x01\xb3\x1b\x07\x05\xee\x06\xcc\xfe\x84\x12\xab\x07~\x08p\x00\x92\x14u\x01\xe4\x12d\xfe9\x08\xb0\x1e\xa6\x02\xb1C?\x18#E\x12\x12\x13^v\x04w\x1d\xe8\x04\x9bf\x1a\x1c\x9b\x0b\xb0\x11\xae%#\x06\xbe\x1f^\x15s.\x92\x10k'`\x0b[ {\x03!\x00 \x1b\xdf(\xec#\xfcH=\x02\x1e\x11!\x07\xba\xedu \xa7\x0e\xdb\x0by\xfb\x91\x05H\x03\xcb\x08\x94\x04\xfd\x13n\xf8\x07\x06d\xfd\xaf\t{\x17\xda$y\x10"
print(np.fromstring(a, dtype=np.int16))

fid=fopen('data','rb');

fid = open('data', 'rb')

signal=fread(fid,data_len,'int16');   %列向量

import numpy as np

signal = np.fromfile(fid, np.int16)  # 转Int16

import numpy as np

signal = np.fromfile('data', np.int16)  # 转Int16

signal1=reshape(signal,2,[]);

signal1 = signal.reshape((-1, 2)).T  

import numpy as np
phase = np.reshape(signal1[0], (-1, 10)).T

y=filter(HP,1,phase(1,:));

from scipy.signal import lfilter
y = lfilter(b=HP, a=1, x=phase[0], axis=0) # 滤波