Python中使用zip函数的七重境界解析

id = [1, 2, 3, 4]
leaders = ['Elon Mask', 'Tim Cook', 'Bill Gates', 'Bai Li']
record = zip(id, leaders)

print(record)
# <zip object at 0x7f266a707d80>

print(list(record))
# [(1, 'Elon Mask'), (2, 'Tim Cook'), (3, 'Bill Gates'), (4, 'Bai Li')]

id = [1, 2, 3, 4]
record = zip(id)
print(list(record))
# [(1,), (2,), (3,), (4,)]

id = [1, 2]
leaders = ['Elon Mask', 'Tim Cook', 'Bill Gates', 'Bai Li']
record = zip(id, leaders)

print(list(record))
# [(1, 'Elon Mask'), (2, 'Tim Cook')]

from itertools import zip_longest
id = [1, 2]
leaders = ['Elon Mask', 'Tim Cook', 'Bill Gates', 'Bai Li']

long_record = zip_longest(id, leaders)
print(list(long_record))
# [(1, 'Elon Mask'), (2, 'Tim Cook'), (None, 'Bill Gates'), (None, 'Bai Li')]

long_record_2 = zip_longest(id, leaders, fillvalue='Top')
print(list(long_record_2))
# [(1, 'Elon Mask'), (2, 'Tim Cook'), ('Top', 'Bill Gates'), ('Top', 'Bai Li')]

record = [(1, 'Elon Mask'), (2, 'Tim Cook'), (3, 'Bill Gates'), (4, 'Bai Li')]
id, leaders = zip(*record)
print(id)
# (1, 2, 3, 4)
print(leaders)
# ('Elon Mask', 'Tim Cook', 'Bill Gates', 'Bai Li')

id = [1, 2, 3, 4]
leaders = ['Elon Mask', 'Tim Cook', 'Bill Gates', 'Bai Li']

# create dict by dict comprehension
leader_dict = {i: name for i, name in zip(id, leaders)}
print(leader_dict)
# {1: 'Elon Mask', 2: 'Tim Cook', 3: 'Bill Gates', 4:'Bai Li'}

# create dict by dict function
leader_dict_2 = dict(zip(id, leaders))
print(leader_dict_2)
# {1: 'Elon Mask', 2: 'Tim Cook', 3: 'Bill Gates', 4: 'Bai Li'}

# update
other_id = [5, 6]
other_leaders = ['Larry Page', 'Sergey Brin']
leader_dict.update(zip(other_id, other_leaders))
print(leader_dict)
# {1: 'Elon Mask', 2: 'Tim Cook', 3: 'Bill Gates', 4: ''Bai Li'', 5: 'Larry Page', 6: 'Sergey Brin'}

products = ["cherry", "strawberry", "banana"]
price = [2.5, 3, 5]
cost = [1, 1.5, 2]
for prod, p, c in zip(products, price, cost):
    print(f'The profit of a box of {prod} is £{p-c}!')
# The profit of a box of cherry is £1.5!
# The profit of a box of strawberry is £1.5!
# The profit of a box of banana is £3!

matrix = [[1, 2, 3], [1, 2, 3]]
matrix_T = [list(i) for i in zip(*matrix)]
print(matrix_T)
# [[1, 1], [2, 2], [3, 3]]