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mysql一条sql查出多个条件不同的sum或count问题

 更新时间：2023年05月29日 09:50:02   作者：码农王山  
这篇文章主要介绍了mysql一条sql查出多个条件不同的sum或count问题，具有很好的参考价值，希望对大家有所帮助。如有错误或未考虑完全的地方，望不吝赐教

一条sql查出多个条件不同的sum或count

最近做java后台遇到很多问题记录一下，有个需求是在一条sql中同时统计到几条条件不一样的sql或count，就用了子查询，希望能帮助到需要的朋友，上代码和效果图：

select 
sum(pzgwjscd) as allJsgm,sbjh.nd as nd, 
( select sum(pzgwjscd) from fm_jh_ws_ptgw ptgw left join fm_sb_jh sbjh on ptgw.sbid = sbjh.id 
where substring(ptgw.xzqh,1,4) LIKE CONCAT ('3301') and ptgw.zt != 0 and sbjh.nd=2017 ) as hzJsgm, 
( select sum(pzgwjscd) from fm_jh_ws_ptgw ptgw left join fm_sb_jh sbjh on ptgw.sbid = sbjh.id 
where substring(ptgw.xzqh,1,4) LIKE CONCAT ('3303') and ptgw.zt != 0 and sbjh.nd=2017) as wzJsgm, 
( select sum(pzgwjscd) from fm_jh_ws_ptgw ptgw left join fm_sb_jh sbjh on ptgw.sbid = sbjh.id 
where substring(ptgw.xzqh,1,4) LIKE CONCAT ('3304') and ptgw.zt != 0 and sbjh.nd=2017 ) as jxJsgm, 
( select sum(pzgwjscd) from fm_jh_ws_ptgw ptgw left join fm_sb_jh sbjh on ptgw.sbid = sbjh.id 
where substring(ptgw.xzqh,1,4) LIKE CONCAT ('3305') and ptgw.zt != 0 and sbjh.nd=2017) as huzJsgm, 
( select sum(pzgwjscd) from fm_jh_ws_ptgw ptgw left join fm_sb_jh sbjh on ptgw.sbid = sbjh.id 
where substring(ptgw.xzqh,1,4) LIKE CONCAT ('3306') and ptgw.zt != 0 and sbjh.nd=2017 ) as sxJsgm, 
( select sum(pzgwjscd) from fm_jh_ws_ptgw ptgw left join fm_sb_jh sbjh on ptgw.sbid = sbjh.id 
where substring(ptgw.xzqh,1,4) LIKE CONCAT ('3307') and ptgw.zt != 0 and sbjh.nd=2017 ) as jhJsgm, 
( select sum(pzgwjscd) from fm_jh_ws_ptgw ptgw left join fm_sb_jh sbjh on ptgw.sbid = sbjh.id 
where substring(ptgw.xzqh,1,4) LIKE CONCAT ('3308') and ptgw.zt != 0 and sbjh.nd=2017 ) as qzJsgm, 
( select sum(pzgwjscd) from fm_jh_ws_ptgw ptgw left join fm_sb_jh sbjh on ptgw.sbid = sbjh.id 
where substring(ptgw.xzqh,1,4) LIKE CONCAT ('3309') and ptgw.zt != 0 and sbjh.nd=2017 ) as zsJsgm, 
( select sum(pzgwjscd) from fm_jh_ws_ptgw ptgw left join fm_sb_jh sbjh on ptgw.sbid = sbjh.id 
where substring(ptgw.xzqh,1,4) LIKE CONCAT ('3310') and ptgw.zt != 0 and sbjh.nd=2017 ) as tzJsgm, 
( select sum(pzgwjscd) from fm_jh_ws_ptgw ptgw left join fm_sb_jh sbjh on ptgw.sbid = sbjh.id 
where substring(ptgw.xzqh,1,4) LIKE CONCAT ('3311') and ptgw.zt != 0 and sbjh.nd=2017 ) as lsJsgm 
from fm_jh_ws_ptgw ptgw 
left join fm_sb_jh sbjh on ptgw.sbid = sbjh.id 
where 1=1 and ptgw.zt != 0 and sbjh.nd=2017 

数据库表

查询结果：

Sql根据不同条件统计总数

经常会遇到根据不同的条件统计总数的问题，一般有两种写法：count和sum都可以

数据准备：

方法一 ：Count

代码：

SELECT
	COUNT(
		CASE
		WHEN age > 20
		AND age < 25 THEN
			1
		ELSE
			NULL
		END
	) AS cnt0,
	COUNT(
		CASE
		WHEN age >= 25
		AND age < 30 THEN
			1
		ELSE
			NULL
		END
	) AS cnt1
FROM
	USER;

结果：

方法二：sum

代码：

SELECT
	SUM(
		CASE
		WHEN age > 20
		AND age < 25 THEN
			1
		ELSE
			0
		END
	) AS cnt0,
	SUM(
		CASE
		WHEN age >= 25
		AND age < 30 THEN
			1
		ELSE
			0
		END
	) AS cnt1
FROM
	USER;

结果：

当然也可以和count代码一样ELSE后面也写为NULL

SELECT
	SUM(
		CASE
		WHEN age > 20
		AND age < 25 THEN
			1
		ELSE
			NULL
		END
	) AS cnt0,
	SUM(
		CASE
		WHEN age >= 25
		AND age < 30 THEN
			1
		ELSE
			NULL
		END
	) AS cnt1
FROM
	USER;

后记

其实原理很简单，count统计的时候有满足条件的就加1，没有满足的变为NULL，我们知道聚合函数统计的时候是忽略null值的；而sum原理和coun相似，不过ELSE后面可以是0或者NULL。

总结

以上为个人经验，希望能给大家一个参考，也希望大家多多支持脚本之家。

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