python 计算两个日期相差多少个月实例代码

import datetime

from dateutil import rrule

d1 = datetime.date(2016, 2, 29)
d2 = datetime.date(2019, 3, 31)

months = rrule.rrule(rrule.MONTHLY, dtstart=d1, until=d2).count()

print(f"months={months}")

import datetime

import calendar as c



d1 = datetime.date(2016, 2, 29)

d2 = datetime.date(2019, 3, 31)



def calmonths(startdate, enddate):

# 计算两个日期相隔月差

samemonthdate = None

try:

samemonthdate = datetime.date(enddate.year, enddate.month,

startdate.day)

except Exception as e:

print(e)

samemonthdate = datetime.date(enddate.year, enddate.month,

c.monthrange(enddate.year,

enddate.month)[1])


holdmonths = 0

decimalmonth = 0.0

if samemonthdate > enddate:

premanthdate = None

try:

premanthdate = datetime.date(enddate.year, enddate.month - 1,

startdate.day)

except Exception as e:

print(e)

premanthdate = datetime.date(enddate.year, enddate.month - 1,

c.monthrange(

enddate.year,

enddate.month - 1)[1])

currmonthdays = (samemonthdate - premanthdate).days

holdmonths = (premanthdate.year - startdate.year

) * 12 + premanthdate.month - startdate.month

decimalmonth = (enddate - premanthdate).days / currmonthdays


elif samemonthdate < enddate:

nextmonthdate = None

try:

nextmonthdate = datetime.date(enddate.year, enddate.month + 1,

startdate.day)

except Exception as e:

nextmonthdate = datetime.date(enddate.year, enddate.month + 1,

c.monthrange(

enddate.year,

enddate.month + 1)[1])

currmonthdays = (nextmonthdate - samemonthdate).days

holdmonths = (samemonthdate.year - startdate.year

) * 12 + samemonthdate.month - startdate.month

decimalmonth = (enddate - samemonthdate).days / currmonthdays


else:

holdmonths = (enddate.year - startdate.year

) * 12 + enddate.month - startdate.month


return holdmonths, decimalmonth


months = calmonths(d1, d2)


print(f"months={months}")