Javascript中toFixed计算错误(依赖银行家舍入法的缺陷)解决方法

console.log(.1+.2);
0.30000000000000004

var num = 0.045;
console.log(num.toFixed(2));
0.04

var num = 0.004;
console.log(num.toFixed(2));
0.00
var num = 0.014;
console.log(num.toFixed(2));
0.01
var num = 0.094;
console.log(num.toFixed(2));
0.09

var num = 0.006;
console.log(num.toFixed(2));
0.01
var num = 0.016;
console.log(num.toFixed(2));
0.02
var num = 0.096;
console.log(num.toFixed(2));
0.10

var num = 0.0051;
console.log(num.toFixed(2));
0.01
var num = 0.0052;
console.log(num.toFixed(2));
0.01
var num = 0.0059;
console.log(num.toFixed(2));
0.01

var num = 0.005;
console.log(num.toFixed(2));
var num = 0.015;
console.log(num.toFixed(2));
var num = 0.025;
console.log(num.toFixed(2));
var num = 0.035;
console.log(num.toFixed(2));
var num = 0.045;
console.log(num.toFixed(2));
var num = 0.055;
console.log(num.toFixed(2));
var num = 0.065;
console.log(num.toFixed(2));
var num = 0.075;
console.log(num.toFixed(2));
var num = 0.085;
console.log(num.toFixed(2));
var num = 0.095;
console.log(num.toFixed(2));

 Number.prototype.toFixed = function(length)
    {
      var carry = 0; //存放进位标志
      var num,multiple; //num为原浮点数放大multiple倍后的数，multiple为10的length次方
      var str = this + ''; //将调用该方法的数字转为字符串
      var dot = str.indexOf("."); //找到小数点的位置
      if(str.substr(dot+length+1,1)>=5) carry=1; //找到要进行舍入的数的位置，手动判断是否大于等于5，满足条件进位标志置为1
      multiple = Math.pow(10,length); //设置浮点数要扩大的倍数
      num = Math.floor(this * multiple) + carry; //去掉舍入位后的所有数，然后加上我们的手动进位数
      var result = num/multiple + ''; //将进位后的整数再缩小为原浮点数
      /*
      * 处理进位后无小数
      */
      dot = result.indexOf(".");
      if(dot < 0){
        result += '.';
        dot = result.indexOf(".");
      }
      /*
      * 处理多次进位
      */
      var len = result.length - (dot+1);
      if(len < length){
        for(var i = 0; i < length - len; i++){
          result += 0;
        }
      }
      return result;
    }