PHP实现的基于单向链表解决约瑟夫环问题示例

<?php
class Node{
  public $value;   // 节点值
  public $nextNode;  // 下一个节点
}
function create($node, $value){
  $node->value = $value;
}
function addNode($node, $value){
  $lastNode = findLastNode($node);
  $nextNode = new Node();
  $nextNode->value = $value;
  $lastNode->nextNode = $nextNode;
}
/* 找到最后的节点 */
function findLastNode($node){
  if(empty($node->nextNode)){
    return $node;
  }else{
    return findLastNode($node->nextNode);
  }
}
/* 删除节点 必须head为引用传值 */
function deleteNode(&$head, $node, $m, $k = 1){
  if($k + 1 == $m){
    if($node->nextNode == $head){
      $node->nextNode = $node->nextNode->nextNode;
      $head = $node->nextNode;
      return $node->nextNode;
    }else{
      $node->nextNode = $node->nextNode->nextNode;
      return $node->nextNode;
    }
  }else{
    return deleteNode($head, $node->nextNode, $m, ++$k);
  }
}
/* 节点数 */
function countNode($head, $node, $count = 1){
  if($node->nextNode == $head){
    return $count;
  }else{
    return countNode($head, $node->nextNode, ++$count);
  }
}
function printNode($head, $node){
  echo $node->value . ' ';
  if($node->nextNode == $head) return;
  printNode($head, $node->nextNode);
}
function show($data){
  echo '<pre>';
  print_r($data);
  echo '</pre>';
}
$head = new Node();
create($head, 1);
addNode($head, 2);
addNode($head, 3);
addNode($head, 4);
addNode($head, 5);
addNode($head, 6);
addNode($head, 7);
addNode($head, 8);
addNode($head, 9);
addNode($head, 10);
addNode($head, 11);
addNode($head, 12);
$lastNode = findLastNode($head);
$lastNode->nextNode = $head;
$count = countNode($head, $head);
$tmpHead = $head;
while ($count > 2) {
  $tmpHead = deleteNode($head, $tmpHead, 3, 1);
  $count = countNode($head, $head);
}
printNode($head, $head);