JavaScript callback回调函数用法实例分析

<div class="imgDiv">
  <div class="search">
    <input class="put" type="text" id="keyWord"/>
    <ul id="tipList"></ul>
</div>

(function (){
  $(function(){
  $("#keyWord").on("keyup",function(event){
    var keyCode = event.keyCode;
    if(keyCode == 38|| keyCode ==40){
      settingTipList(keyCode);
      return false;
    }
    var keyWord = $(this).val();
    getTipList(keyWord);
  });
  var index = -1;
  function settingTipList(keyCode){
    if(keyCode == 38){
      index--;
    }else{
      index++;
    }
    var size = $("#tipList li").size();
    index =index % size;
    $("#tipList li").removeClass("active").eq(index).addClass("active");
    var selectLiContent = $("#tipList li").eq(index).html();
    $("#keyWord").val(selectLiContent);
  };
  //获取数据
  function getTipList(keyWord){
    var url = "https://sp0.baidu.com/5a1Fazu8AA54nxGko9WTAnF6hhy/su";
    var data = {
      wd:keyWord,
      cb:"hhh"
    };
    $.ajax({
      url:url,
      data:data,
      type:"GET",
      dataType:"jsonp",
      jsonpCallback:"hhh",
      success:function(data){
        var tipList = data.s;
        handleData(tipList)
      },
      error:function(error){
        alert("接口出错")
      }
    });
  }
  });
  function handleData(tipList){
    var tipHTML= "";
    for(var i in tipList){
      var text = tipList[i];
      tipHTML += "<li>"+text+"</li>"
    }
    $("#tipList").css({"opacity":"1"});
    $("#tipList").html(tipHTML);
  }
})()
//如果不写jsonpCallback、后面jsonpCallback“”空置、直接跳出“接口出错了。