django反向解析URL和URL命名空间的方法

from django.conf.urls import url
from . import views

urlpatterns = [
 #...
 url(r'^articles/([0-9]{4})/$', views.year_archive, name='news-year-archive'),
 #...
]

<a href="{% url 'news-year-archive' 2012 %}" rel="external nofollow" >2012 Archive</a>

from django.urls import reverse
from django.http import HttpResponseRedirect

def redirect_to_year(request):
 # ...
 year = 2006
 # ...
 return HttpResponseRedirect(reverse('news-year-archive', args=(year,)))

# 主url.py
urlpatterns = [
 ...
 url(r'^bbb/', include("test_namespace2.urls")),
 url(r'^ccc/', include("test_namespace2.urls")),
 ...
]

# test_namespace2/url.py
app_name = "app02"

urlpatterns = [
 url(r'aaa/$', views.aaa, name="index"),
]

# test_namespace2/view.py
def aaa(request):
 return HttpResponse(reverse("app02:index"))

# 主url.py
urlpatterns = [
 ...
 url(r'^bbb/', include("test_namespace2.urls", namespace='bbb')), # 加入了namespace
 url(r'^ccc/', include("test_namespace2.urls", namespace='ccc')),
 ...
]

# test_namespace2/view.py
def aaa(request):
 return HttpResponse(reverse("app02:index", current_app=request.resolver_match.namespace)) # 使用namespace

urlpatterns = [
 url(r'^polls/', include('polls.urls',namespace='test')),
]

app_name = 'polls'
urlpatterns = [
 #...
 url(r'^$', views.index, name='index'),
 #...

reverse('polls:index', current_app=request.resolver_match.namespace)

{% url 'polls:index' %}