python3中zip()函数使用详解

* coding: utf-8 * 

print(‘=‘*10 + “zip()函数单个参数” + ‘=‘*10) 
list1 = [1, 2, 3, 4] 
tuple1 = zip(list1)

list2=list(tuple1)

print(“zip对象转化为列表：\n”, list(tuple1))#值为[(1,), (2,), (3,), (4,)] 
print(“zip对象转化为列表：\n”, list(tuple1))#值为[]

print(“list2输出的列表1为:\n”,list2) 
print(“list2输出的列表2为:\n”,list2) 

print(‘=‘*10 + “zip()函数有2个参数” + ‘=‘*10) 
m = [[1, 2, 3], [4, 5, 6], [7, 8, 9]] 
n = [[2, 2, 2], [3, 3, 3], [4, 4, 4]] 
p = [[2, 2, 2], [3, 3, 3]]

print(‘=‘*10 + “矩阵点乘” + ‘='10)#左右两端各有10个 
print([x*y for a, b in zip(m, n) for x, y in zip(a, b)])

[2, 4, 6, 12, 15, 18, 28, 32, 36]

print(‘=‘*10 + “矩阵相加,相减” + ‘=‘*10) 
print([x+y for a, b in zip(m, n) for x, y in zip(a, b)])

[3, 4, 5, 7, 8, 9, 11, 12, 13]

m5=[1,2,3] 
n5=[4,5,6] 
k5=[7,8,9] 
zip5=zip(m5,n5,k5)

print(“list(zip5):”,list(zip5))不能输出，否则zip(*zip5)

m6,n6,k6=zip(*zip5) 
print(“m6:”,m6)#m6: (1, 2, 3) 
print(“n6:”,n6)#n6: (4, 5, 6) 
print(“k6:”,k6)#k6: (7, 8, 9)

print(‘=‘*10 + “*zip()函数” + ‘=‘*10) 
m = [[1, 2, 3], [4, 5, 6], [7, 8, 9]] 
n = [[2, 2, 2], [3, 3, 3], [4, 4, 4]]

print(“zip(m, n)返回:\n”, zip(m, n)) # 
print(“*zip(m, n)返回:\n”, *zip(m, n))

*zip(m, n)返回:([1, 2, 3], [2, 2, 2]) ([4, 5, 6],[3, 3, 3]) ([7, 8, 9], [4, 4, 4])

print(“list(zip(m, n))返回:\n”, list(zip(m, n)))

list(zip(m, n))返回: [([1, 2, 3], [2, 2, 2]), ([4, 5, 6], [3, 3, 3]), ([7, 8, 9], [4, 4, 4])]

m2, n2 = zip(*zip(m, n))#先合到一块 
print(“m2:”,m2)#([1, 2, 3], [4, 5, 6], [7, 8, 9]) 
print(“n2:”,n2)#([2, 2, 2], [3, 3, 3], [4, 4, 4]) 
print(m == list(m2) and n == list(n2))#true