Python判断telnet通不通的实例

#!/usr/bin/env python
# coding: utf8
 
import telnetlib
import time
import codecs
import os
 
# telnet host
def telnetdo(host, statusFile):
 status1 = 'telnet success'
 status2 = 'telnet faild'
 for ipAdd in host:
 # get now time
 nowTime = time.strftime('%Y-%m-%d %H:%M:%S',time.localtime(time.time()))
 try:
  t = telnetlib.Telnet(ipAdd, port=23, timeout=1)
  writeToText(nowTime, ipAdd, status1, statusFile)
 except:
  writeToText(nowTime, ipAdd, status2, statusFile) 
  
# write status information to txt
def writeToText(nowTime, ipAdd, status, statusFile):
 s_text = 'TIME:' + nowTime + '\t' + 'IP:' + ipAdd + '\t' + 'STATUS:' + status + '\r\n'
 
 if '0' == judgeFile(statusFile):
 with open(statusFile, 'a') as f:
  f.write(s_text)
  f.close() 
 if '1' == judgeFile(statusFile):
 with open(statusFile, 'w') as f:
  f.write(s_text)
  f.close() 
 
 
  
# Determine whether statusFile exists 
# 0: exists
# 1: no exists
def judgeFile(statusFile):
 if os.path.exists(statusFile):
 return '0'
 else:
 return '1'
  
if __name__ == "__main__":
 host = ['192.168.1.254', '192.168.1.100']
 # write file
 statusFile = '/root/telnetStatus.txt'
 i = 7200
 while i:
 telnetdo(host, statusFile)
 time.sleep(2)
 i = i - 1