python实现合并两个排序的链表

def Merge(self, pHead1, pHead2):
 if not pHead1:
  return pHead2
 if not pHead2:
  return pHead1
 mainHead = pHead1 if pHead1.val <= pHead2.val else pHead2
 secHead = pHead2 if mainHead == pHead1 else pHead1
 mergeHead = mainHead
 mainNext = mainHead.next
 while mainNext and secHead:
  if secHead.val <= mainNext.val:
   mainHead.next = secHead
   secHead = secHead.next
   mainHead.next.next = mainNext
   mainHead = mainHead.next
  else:
   mainHead = mainNext
   mainNext = mainNext.next
 if not mainNext:
  mainHead.next = secHead
 return mergeHead

def Merge(self, pHead1, pHead2):
 if not pHead1:
  return pHead2
 if not pHead2:
  return pHead1
 if pHead1.val <= pHead2.val:
  pHead1.next = self.Merge(pHead1.next, pHead2)
  return pHead1
 else:
  pHead2.next = self.Merge(pHead1, pHead2.next)
  return pHead2

class Solution:

 def Merge(self, pHead1, pHead2):
  if not pHead1:
   return pHead2
  if not pHead2:
   return pHead1
  if pHead1.val <= pHead2.val:
   pHead1.next = self.Merge(pHead1.next, pHead2)
   return pHead1
  else:
   pHead2.next = self.Merge(pHead1, pHead2.next)
   return pHead2

 def getNewChart(self, list):
  if list:
   node = ListNode(list.pop(0))
   node.next = self.getNewChart(list)
   return node

class ListNode:
 def __init__(self, x):
  self.val = x
  self.next = None

if __name__ == '__main__':
 list1 = [1, 3, 5]
 list2 = [0, 1, 4]
 testList1 = Solution().getNewChart(list1)
 testList2 = Solution().getNewChart(list2)
 final = Solution().Merge(testList1, testList2)
 while final:
  print(final.val, end=" ")
  final = final.next