Python实现 版本号对比功能的实例代码

def abc(str1, str2):
  if str1 == "" or str2 == "":
    print("输入包含空字符串，请重新输入")
    return ("输入包含空字符串，请重新输入")
  elif str1 == str2:
    print("2个版本号相同")
    return ("2个版本号相同")
  elif int(str1[0]) > int(str2[0]):
    print("版本1的版本号更大")
    return ("版本1的版本号更大")
  elif int(str1[0]) < int(str2[0]):
    print("版本2的版本号更大")
    return ("版本2的版本号更大")
  abc(str1[2:], str2[2:])
abc("5.3.2", "5.1.9")

# -*- coding: utf-8 -*-
__author__ = 'ypp'
import re
def versionCompare(v1="1.1.1", v2="1.2"):
  v1_check = re.match("\d+(\.\d+){0,2}", v1)
  v2_check = re.match("\d+(\.\d+){0,2}", v2)
  if v1_check is None or v2_check is None or v1_check.group() != v1 or v2_check.group() != v2:
    return "版本号格式不对，正确的应该是x.x.x,只能有3段"
  v1_list = v1.split(".")
  v2_list = v2.split(".")
  v1_len = len(v1_list)
  v2_len = len(v2_list)
  if v1_len > v2_len:
    for i in range(v1_len - v2_len):
      v2_list.append("0")
  elif v2_len > v1_len:
    for i in range(v2_len - v1_len):
      v1_list.append("0")
  else:
    pass
  for i in range(len(v1_list)):
    if int(v1_list[i]) > int(v2_list[i]):
      return "v1大"
    if int(v1_list[i]) < int(v2_list[i]):
      return "v2大"
  return "相等"
# 测试用例
print(versionCompare(v1="", v2="")) 
print(versionCompare(v1="1.0.a", v2="d.0.1"))
print(versionCompare(v1="1.0.1", v2="1.0.1"))
print(versionCompare(v1="1.0.2", v2="1.0.1"))
print(versionCompare(v1="1.0.1", v2="1.0.2"))
print(versionCompare(v1="1.0.11", v2="1.0.2"))