详解es6新增数组方法简便了哪些操作

let a = [1,2,2,3,3,4,5];
let b = [a[0]];
for(let i = 0; i < a.length; i++){
  let flag = false;
  for(let j = 0; j < b.length; j++){
    if( a[i] === b[j] ){
      flag = true;
      break;
    }
  }
  if( !flag ){
    b.push(a[i])
  }
}
console.log(b) // [1,2,3,4,5]

let a = [1,2,2,3,3,4,5];
let b = Array.from(new Set(a))
console.log(b) // [1,2,3,4,5]

// 取出数组中name为kele的数组集合
let a = [
  {
    name: 'kele',
    title: '可口可乐'
  },
  {
    name: 'kele',
    title: '芬达'
  },
  {
    name: 'wlg',
    title: '王老吉'
  }
]

let b = [];

for(let i = 0; i < a.length; i++){
  if( a[i].name === 'kele' ){
    b.push(a[i])
  }
}

console.log(b) //[{name: 'kele', title: '可口可乐'},{name: 'kele', title: '芬达'}]

let a = [
  {
    name: 'kele',
    title: '可口可乐'
  },
  {
    name: 'kele',
    title: '芬达'
  },
  {
    name: 'wlg',
    title: '王老吉'
  }
]

let b = a.filter(item => item.name === 'kele');

console.log(b) //[{name: 'kele', title: '可口可乐'},{name: 'kele', title: '芬达'}]

let a = [1,2,3,4,5];
let b = a.every(item => item > 2);
console.log(b) // false

let a = [1,2,3,4,5];
let b = a.some(item => item > 2);
console.log(b) // true

let a = [1,2,3,4,5];
let b = a.find(item => item > 2);
console.log(b) // 3

let a = [1,2,3,4,5];
let b = a.findIndex(item => item > 2);
console.log(b) // 2 符合条件的为元素3 它的索引为2

let a = [1,2,3,4,5];
let b = a.includes(2);
console.log(b) // true

let a = [1,2,3,4,5];
let b = a.map(item => item * 2);
console.log(b) // [2,4,6,8,10]

/** 第一种 **/
let a = [1,2,3];
let b = a.reduce((i, j) => {
 return i + j;
}, 0);
console.log(b) // b
/** 第二种 **/
let a = [1,2,3];
let b = a.reduce((i,j) => {
 i.push(j)
 return i
},[0])
console.log(b) // [0,1,2,3]

let a = [1,2,3];
let b = [4,5,6];
let c = [...a,...b];
console.log(c) // [1,2,3,4,5,6];