JS学习笔记之数组去重实现方法小结

 let arr=[0,1,23,'1',4,2,8,5,5,6,9,'asdasd','5']

 console.time("set")
  let type1=new Set(arr)
  console.log(type1)
  type1=[...type1]
  console.log(type1)
  console.timeEnd("set")

console.time("indexOf")
  let type2=[]
  arr.forEach(function(item,index){
    if(type2.indexOf(item)<0){
      type2.push(item)
    }
  })
  console.log(type2)
  console.timeEnd("indexOf")

console.time("splice")
let arr2=[0,1,23,'1',4,2,8,5,5,6,9,'asdasd','5']
  for(let i=0;i<arr2.length;i++){
    for(let j=i+1;j<arr2.length;j++){
      if(arr2[i]===arr2[j]){
        arr2.splice(i,1)
      }
    }
  }
  console.log(arr2)
console.timeEnd("splice")

console.time("obj属性")
let obj1={}
let type4=[]
arr.forEach(function(item,index){
  let tf=typeof item
  if(!obj1[tf+"_"+item]){
    obj1[tf+"_"+item]=true
  }
})
console.log(obj1)
for(item in obj1){
  type4.push(item.split("_")[0].toLowerCase()=="number"?+item.split("_")[1]:item.split("_")[1])
}
obj1=null;
console.log(type4)
console.timeEnd("obj属性")

console.time("sort排序")
let arr3=[0,1,23,'1',4,2,8,5,5,6,9,'asdasd','5']
arr3.sort()
for(let i=0;i<arr3.length;i++){
  if(arr3[i]===arr3[i+1]){
    arr3.splice(i,1)
  }
}
console.log(arr3)
console.timeEnd("sort排序")