python里 super类的工作原理详解

def super(cls, inst):
  mro = inst.__class__.mro()
  return mro[mro.index(cls) + 1]

class A:
  def __init__(self):
    self.n = 2

  def add(self, m):
    print('\n\nself is {0} @A.add'.format(self))
    self.n += m


class B(A):
  def __init__(self):
    self.n = 3

  def add(self, m):
    print('\n\nself is {0} @B.add'.format(self))
    super(B, self).add(m)
    self.n += 3


class C(A):
  def __init__(self):
    self.n = 4

  def add(self, m):
    print('\n\nself is {0} @C.add'.format(self))
    super(C, self).add(m)
    self.n += 4


class D(B, C):
  def __init__(self):
    self.n = 5

  def add(self, m):
    print('\n\nself is {0} @D.add'.format(self))

    print(super(D, self).__self__)
    print(super(D, self).__thisclass__)

    super(D, self).add(m)
    self.n += 5


if __name__ == '__main__':

  print(D.mro())
  d = D()
  d.add(2) # 等于是： D.add(d, 2)
  print(d.n)

[<class '__main__.D'>, <class '__main__.B'>, <class '__main__.C'>, <class '__main__.A'>, <class 'object'>]

<__main__.D object at 0x101ef16d8>


self is <__main__.D object at 0x101ef16d8> @D.add
<__main__.D object at 0x101ef16d8>
<class '__main__.D'>


self is <__main__.D object at 0x101ef16d8> @B.add


self is <__main__.D object at 0x101ef16d8> @C.add


self is <__main__.D object at 0x101ef16d8> @A.add
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