python sorted函数的小练习及解答

class_mates = {'sherry':[18,'male'],'june':[20,'female'],'flora':[19,'female'],'alina':[21,'male']}
class Person(object):
　　def __init__(self,name,age):
　　self.name = name
p1 = Person('sherry',20)
p2 = Person('june',20)
if p1<p2:
print('p1:{} less than p2:{}'.format([p1.name,p1.age],[p2.name,p2.age]))
else:
print('p1:{} gte than p2:{}'.format([p1.name,p1.age],[p2.name,p2.age]))

def get_first(info):
   first_value = info[0][0]
   return first_value
 na = sorted(datas,key=get_first)
 print(na)

 def age_sort(info):
   return info[1]
 print(sorted(datas,key=age_sort))

class_mates = {'sherry':[18,'male'],'june':[20,'female'],'flora':[19,'female'],'alina':[21,'male']}
class Person(object):
  def __init__(self,name,age):
    self.name = name
    self.age = age
  def __lt__(self,others):
    if(self.age<others.age):
      return 1
    elif(self.age==others.age): 
      if(self.name[0]<others.name[0]):
        return 1
      else:
        return 0
    return 0
p1 = Person('sherry',20)
p2 = Person('june',20)
if p1<p2:
  print('p1:{} less than p2:{}'.format([p1.name,p1.age],[p2.name,p2.age]))
else:
  print('p1:{} gte than p2:{}'.format([p1.name,p1.age],[p2.name,p2.age]))