python超时重新请求解决方案

# -*- coding: utf-8 -*-
import random
import time
 
import eventlet
from retrying import retry
 
eventlet.monkey_patch()
 
 
class RetryTimeOutException(Exception):
  def __init__(self, *args, **kwargs):
    pass
 
 
def retry_if_timeout(exception):
  """Return True if we should retry (in this case when it's an IOError), False otherwise"""
  return isinstance(exception, RetryTimeOutException)
 
 
def retry_fun(retries=3, timeout_second=2):
  """
  will retry ${retries} times when process time beyond ${timeout_second} ;
  :param retries: The retry times
  :param timeout_second: The max process time
  """
 
  def retry_decor(func):
    @retry(stop_max_attempt_number=retries, retry_on_exception=retry_if_timeout)
    def decor(*args, **kwargs):
      print("In retry method..")
      pass_flag = False
      with eventlet.Timeout(timeout_second, False):
        r = func(*args, **kwargs)
        pass_flag = True
        print("Success after method.")
      if not pass_flag:
        raise RetryTimeOutException("Time out..")
      print("Exit from retry.")
      return r
 
    return decor
 
  return retry_decor
 
 
def do_request():
  print("begin request...")
  sleep_time = random.randint(1, 4)
  print("request sleep time: %s." % sleep_time)
  time.sleep(sleep_time)
  print("end request...")
  return True
 
 
@retry_fun(retries=3)
def retry_request():
  r = do_request()
  print(r)
 
 
if __name__ == '__main__':
  retry_request()