python 贪心算法的实现

def shortNum(a):
  coins = [1,5,10,25,100]
  out = []
  coins = coins[::-1]

  for i in coins:
    num = a//i
    out=out+[i,]*num
    a = a-num*i
    if a<=0:
      break
  return out
a = 36
print(shortNum(a))

# 任务规划
from collections import OrderedDict
task = OrderedDict()
task['r1'] = [0,4]
task['r2'] = [5,8]
task['r3'] = [10,13]
task['r4'] = [15,18]
task['r5'] = [7,11]
task['r6'] = [2,6]
task['r7'] = [2,6]
task['r8'] = [2,6]
task['r9'] = [12,16]
task['r10'] = [12,16]
task['r11'] = [12,16]
task['r12'] = [0,3]


listTask = list(task.items())
# 根据bi进行排序，结束时间早的在前面（冒泡排序）
for i in range(len(listTask)-1):
  for j in range(len(listTask)-i-1):
    if listTask[j][1][1] > listTask[j+1][1][1]:
      listTask[j],listTask[j+1]=listTask[j+1],listTask[j]
print(listTask)
out = []
out.append(listTask.pop(0))
def isValid(temp,out):
  for k in range(len(out)):
    if temp[1][0]<out[k][1][1]:
      # 相交
      return False
  return True

for j in range(len(listTask)):
  temp = listTask.pop(0)
  # 判断是否相交
  #   相交则continue
  #   不相交则out.append(temp)
  for k in range(len(out)):
    if isValid(temp,out):
      out.append(temp)
    # else:continue 语句可以不写
    else:
      continue
print(out)