如何基于Python实现word文档重新排版

from docx import Document

# 打开文件
srcdocx = Document(‘src.docx‘)
# 遍历所有段落
for p in srcdocx.paragraphs:
  print(p.text)

from docx import Document

# 判断字符串是否为数字
def is_number(s):
  try:
    float(s)
    return True
  except ValueError:
    pass
  try:
    import unicodedata
    unicodedata.numeric(s)
    return True
  except (TypeError, ValueError):
    pass
  return False

# 修正错误题目序号
# src,源字符串 nPos,序号结束下标 cnt,正确序号
def changeNum(src,nPos,cnt):
  s = src[:0] + src[nPos:]
  str_list = list(s)
  str_list.insert(0, str(cnt))
  dest = ‘‘.join(str_list)
  return dest
  
# 源文档
srcdocx = Document(‘src.docx‘)
# 目标文档
outDocx = Document()
idx = 0 # 遍历下标
length = len(srcdocx.paragraphs) # 总段落数
cnt = 1 # 遍历序号
sum = 1 # 修改总次数

while(1):
  if idx >= length:
    break
  src = srcdocx.paragraphs[idx].text
  # 实现需求1,3,5
  if((src == "窗体底端") or (src =="窗体顶端") or (src == "") or (is_number(src))) :
    print(f"正在修改第{sum}处错误 {src}")
    sum = sum + 1 # 计算修改的次数
    idx = idx + 1
    continue
  # 实现需求2
  nPos1 = src.find("．")
  if nPos1 != -1 :
    # 查找到有序号的行
    dest = changeNum(src,nPos1,cnt)
    print(f"正在修改第{sum}处错误 {src}")
    sum = sum + 1 # 计算修改的次数
    cnt = cnt + 1 # 序号后移
    outDocx.add_paragraph(dest) # 写入数据到新word
  # 实现需求4
  nPos2 = src.find(‘、‘)
  if nPos2 != -1 :
    src2 = srcdocx.paragraphs[idx+1].text
    outDocx.add_paragraph(src+src2)
    idx = idx + 1
    print(f"正在修改第{sum}处错误 {src},{src2}")
    sum = sum + 1 # 计算修改的次数
  idx = idx + 1
  
outDocx.save(‘out.docx‘)
print(f"修改完成！共计{sum}个错误！")