C++和python实现阿姆斯特朗数字查找实例代码

#include <iostream>
using namespace std;
int main()
{
	int n, r, sum=0, temp; 
	cout<<"Enter the Number= "; 
	cin>>n; 
	temp=n; 
	while(n>0) 
	{ 
		r=n%10; 
		sum=sum+(r*r*r); 
		n=n/10; 
	} 
	if(temp==sum) 
		cout<<"Armstrong Number."<<endl; 
	else 
		cout<<"Not Armstrong Number."<<endl; 
	return 0;
}

num = int(input("请输入一个数字："))
sum= 0
n = len(str(num))
temp = num
while temp >0:
 digit = temp %10 # 获取个位数字
 sum += digit**n # 对计算结果进行累加
 temp //= 10
if num == sum :
 print("太棒了！",num,"是阿姆斯特朗数")
else:
 print("很遗憾！",num,"不是阿姆斯特朗数")

lower = int(input("最小值："))
upper = int(input("最大值："))
print("下面是你想要从{}到{}之间的阿姆斯特朗数\n".format(lower,upper))
for num in range(lower,upper+1):
 sum = 0
 n = len(str(num))
 temp = num
 while temp >0:
  digit = temp %10 # 获取个位数字
  sum+= digit**n # 对计算结果进行累加

  temp //= 10
 if num == sum:
  print(num)

#include <iostream>
using namespace std;

int test(int a,int b,int c,int d)
{
	if(a)return a*a*a*a+b*b*b*b*b+c*c*c*c+d*d*d*d*d;
	if(b)return b*b*b+c*c*c+d*d*d;
	if(c)return c*c+d*d;
	if(d)return d;
}
void func(int min, int max)
{
	if(min<=0||min>=max||max<0||max>9999)
	{
		cout << "error!" << endl;
	}
	int a,b,c,d;
	for(int i=min;i<=max;i++)
	{
		a = i/1000;
		b = (i%1000)/100;
		c = (i%100)/10;
		d = i%10;
		if(i==test(a,b,c,d))
			cout << i << endl;
	}
}

int main()
{
	int min,max;
	cin >> min;
	cin >> max;

	func(min,max);

	system("pause");
	return 0;
}