浅谈Python列表嵌套字典转化的问题

{'a' : 97，'b' : 98，'c' : 99 ，'d' : 100，'e' : 101，。。。。。}

{'a' : 97}, {'b' : 98}, {'c' : 99}, {'d' : 100}, {'e' : 101}, ...........---------》 [（'a' , 97）],[（'b' : 98）],........

#coding: utf-8
import types
#获取字典中的objkey对应的值，适用于字典嵌套
#dict:字典
#objkey:目标key
#default:找不到时返回的默认值
def dict_get(dict, objkey, default):
 tmp = dict
 for k,v in tmp.items():
  if k == objkey:
   return v
  else:
   if type(v) is types.DictType:
    ret = dict_get(v, objkey, default)
    if ret is not default:
     return ret
 return default
#如
dicttest={"result":{"code":"110002","msg":"设备设备序列号或验证码错误"}}
ret=dict_get(dicttest, 'msg', None)
print(ret)

 "network": {
  "tls": [],
  "udp": [
   {
    "src": "192.168.56.102",
    "dst": "114.114.114.114",
    "offset": 2372,
    "time": 9.506472110748291,
    "dport": 53,
    "sport": 51394
   },
   {
    "src": "192.168.56.102",
    "dst": "114.114.114.114",
    "offset": 2611,
    "time": 2.232347011566162,
    "dport": 53,
    "sport": 53604
   }]
   }
for k,v in mydict.items():
   if type(v) is types.ListType:
    for val in v:
     if type(val) is types.DictType:
      for key,value in val.items():
       print("%s:%s"%(key,value))
   else:
    print("%s:%s"%(k,v))