python链接sqlite数据库的详细代码实例

import sqlite3
conn = sqlite3.connect("test.db")
print("成功创建数据库")

c = conn.cursor()     #获取游标
sql = '''
    create table company
        (id int primary key not null,
        name text not null,
        age int not null,
        address char(50),
        salary real);
'''
c.execute(sql)      #执行sql语句
conn.commit()       #提交数据库操作
conn.close()        #关闭数据库链接
print("成功建表")

conn = sqlite3.connect("test.db")
print("成功打开数据库")
c = conn.cursor()     #获取游标
sql1 = '''
    insert into company (id,name,age,address,salary)
     values (1,'张三',32,"成都",8000);

'''
sql2 = '''
    insert into company (id,name,age,address,salary)
     values (2,'李四',30,"深圳",15000);

'''
c.execute(sql1)     #执行sql语句
c.execute(sql2)
conn.commit()       #提交数据库操作
conn.close()        #关闭数据库链接
print("成功插入数据")

conn = sqlite3.connect("test.db")
print("成功打开数据库")
c = conn.cursor()  # 获取游标
sql = '''
   select id,name,address,salary from company
'''

cursor = c.execute(sql)  # 执行sql语句
for row in cursor:
    print("id = ",row[0])
    print("name = ",row[1])
    print("address = ",row[2])
    print("salary = ",row[3],"\n")

conn.close()  # 关闭数据库链接
print("成功查找数据")