详解Python字典的运算

stocks = {
    'ACME': 45.23,
    'AAPL': 612.78,
    'IBM': 205.55,
    'HPQ': 37.20,
    'FB': 10.75
}

# 取出value值最小的键值对
min_price = min(zip(stocks.values(), stocks.keys()))
print(min_price)
"""
结果：
(10.75, 'FB')
"""
# 按value值的大小排序
stock_sorted = sorted(zip(stocks.values(), stocks.keys()))
print(stock_sorted)
"""
结果：
[(10.75, 'FB'), (37.2, 'HPQ'), (45.23, 'ACME'), (205.55, 'IBM'), (612.78, 'AAPL')]
"""

price_and_name = zip(stocks.values(), stocks.keys())
min_price = min(price_and_name)
print(min_price)
"""
结果：
(10.75, 'FB')
"""
max_price = max(price_and_name)
print(max_price)
"""
结果：
ValueError: max() arg is an empty sequence
"""

min(stocks)  # return 'AAPL'
max(stocks)  # return 'IBM'

min(prices.values())  # return 10.75
max(prices.values()) # return 612.78

min(prices, key=lambda k: prices[k]) # return 'FB'
max(prices, key=lambda k: prices[k]) # return 'AAPL'

min_value = stocks[min(stocks, key=lambda k: stocks[k])] # return 10.75
max_value = stocks[max(stocks, key=lambda k: stocks[k])] # return 612.78