深入理解 Go 中的字符串

>>> hi = "Hello"
>>> hi
'Hello'
>>> hi[0] = 'h'
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: 'str' object does not support item assignment
>>>

package main
import "fmt"
func main() {
var hello = "Hello"
hello[1] = 'h'
fmt.Println(hello)
}
// # command-line-arguments
// string_in_go/main.go:8:11: cannot assign to hello[1] (strings are immutable)

type StringHeader struct {
Data uintptr // Data 指向底层的字符数组
Len int // Len 用来表示字符串的长度
}

package main
import "fmt"
func main() {
var hello = "Hello"
for i := 0; i < len(hello); i++ {
fmt.Printf("%x ", hello[i])
}
}
// Output: 48 65 6c 6c 6f

func (s *scanner) stdString() {
ok := true
s.nextch()
for {
if s.ch == '"' {
s.nextch()
break
}
if s.ch == '\\' {
s.nextch()
if !s.escape('"') {
ok = false
}
continue
}
if s.ch == '\n' {
s.errorf("newline in string")
ok = false
break
}
if s.ch < 0 {
s.errorAtf(0, "string not terminated")
ok = false
break
}
s.nextch()
}
s.setLit(StringLit, ok)
}
func (s *scanner) rawString() {
ok := true
s.nextch()
for {
if s.ch == '`' {
s.nextch()
break
}
if s.ch < 0 {
s.errorAtf(0, "string not terminated")
ok = false
break
}
s.nextch()
}
// We leave CRs in the string since they are part of the
// literal (even though they are not part of the literal
// value).
s.setLit(StringLit, ok)
}