python语法之通过value找key问题

raw_dict={'domain_id': '$domain_id', 'enabled': '$enabled', 'name': '$username'}
 
key_list = list(filter(lambda k: raw_dict.get(k) == "$domain_id", raw_dict.keys()))
print(key_list) # ['enabled', 'name']

newdict = dict(zip(raw_dict.values(),raw_dict.keys())) #字典的反转，但是如果两个key的value一样，反转后，只会保留一个key
print(newdict)

    def removeParm(self,srcInterParm,parms):
        #去除无用的parm
        pattern = re.compile(r'\$(.*?)\'')
        parmlist =re.findall(pattern,str(srcInterParm))#获取到所有$parm变量名
        noexistParm = []
        for value in parmlist:#验证parm是否在传参中包含
            if not parms.keys().__contains__(value):
                noexistParm.extend(list(filter(lambda k: srcInterParm.get(k) == '$'+value, srcInterParm.keys())))
        for key in noexistParm:
            srcInterParm.pop(key)
        return srcInterParm
 
    print(t.removeParm({'domain_id': '$domain_id', 'enabled': '$enabled', 'name': '$username'},{}))
#打印结果为{}

d = {"1": 9, "2": 0, "3": 7, "6": 3, "0": 4, "4": 1}
value_1 = max(d, key=d.get)
print(value_1)
value_2 = max(d,key=lambda x:d[x])
print(value_2)

value_3 =sorted(d,key=lambda x:d[x])[-1]
print(value_3)