Go语言题解LeetCode599两个列表的最小索引总和

输入: list1 = ["Shogun", "Tapioca Express", "Burger King", "KFC"]，list2 = ["Piatti", "The Grill at Torrey Pines", "Hungry Hunter Steakhouse", "Shogun"]
输出: ["Shogun"]
解释: 他们唯一共同喜爱的餐厅是“Shogun”。

输入:list1 = ["Shogun", "Tapioca Express", "Burger King", "KFC"]，list2 = ["KFC", "Shogun", "Burger King"]
输出: ["Shogun"]
解释: 他们共同喜爱且具有最小索引和的餐厅是“Shogun”，它有最小的索引和1(0+1)。

class Solution {
    public String[] findRestaurant(String[] list1, String[] list2) {
            if(list1 == null||list2 == null){
                return null;
            }
            HashMap<String,Integer> bucket = new HashMap<>();
            for(int i = 0;i < list1.length;i++){
                bucket.put(list1[i],i);
            }
            List<String> res = new ArrayList<>();
            int minIndexSum = Integer.MAX_VALUE;
            for(int i = 0;i< list2.length;i++){
                if(bucket.containsKey(list2[i])){
                    if(bucket.get(list2[i])+i<minIndexSum){
                        minIndexSum = bucket.get(list2[i])+i;
                        res.clear();
                        res.add(list2[i]);
                    }else if(bucket.get(list2[i])+i == minIndexSum){
                        res.add(list2[i]);
                    }
                }
            }
            return res.toArray(new String[res.size()]);
    }
}