浅谈golang的json.Unmarshal的坑

package main

import (
   "encoding/json"
   "fmt"
)

func main() {
   jsonStr := `{"number":1234567}`
   result := make(map[string]interface{})
   err := json.Unmarshal([]byte(jsonStr), &result)
   if err != nil {
      fmt.Println(err)
   }
   fmt.Println(result) // map[number:1.234567e+06]

}

//
// To unmarshal JSON into an interface value,
// Unmarshal stores one of these in the interface value:
//
// bool, for JSON booleans
// float64, for JSON numbers
// string, for JSON strings
// []interface{}, for JSON arrays
// map[string]interface{}, for JSON objects
// nil for JSON null
//

func main() {
   jsonStr := `{"number":1234567}`
   result := make(map[string]interface{})
   err := json.Unmarshal([]byte(jsonStr), &result)
   if err != nil {
      fmt.Println(err)
   }
   fmt.Println(int(result["number"].(float64)))

   // 输出
   // 1234567
}

func main() {
   type Num struct {
      Number int `json:"number"`
   }

   jsonStr := `{"number":1234567}`
   var result Num
   err := json.Unmarshal([]byte(jsonStr), &result)
   if err != nil {
      fmt.Println(err)
   }
   fmt.Println(result)

   // 输出
   // {1234567}
}