tkinter如何实现打开文件对话框并获取文件绝对路径

# 首先，导入模块
import tkinter.filedialog
 
# 此处省略父容器的定义 ...
 
# 第2步，定义按钮并指定触发函数self.Command1_Cmd
self.style.configure('Command1.TButton',font=('宋体',9))
self.Command1 = Button(self.Frame1, text='打开文件', command=self.Command1_Cmd, style='Command1.TButton')
self.Command1.place(relx=0.836, rely=0.107, relwidth=0.093, relheight=0.111)
 
# 第3步，定义按钮触发函数，event=None不能省略
def Command1_Cmd(self, event=None):
      # tkinter提供的askopenfilename函数可以实现打开文件对话框的效果，其返回值为所选文件的绝对路径
      filename = tkinter.filedialog.askopenfilename()
      print(filename)

from tkinter import *
from tkinter.filedialog import askdirectory

def selectPath():
    path_ = askdirectory()
    path.set(path_)

root = Tk()
path = StringVar()

Label(root,text = "目标路径:").grid(row = 0, column = 0)
Entry(root, textvariable = path).grid(row = 0, column = 1)
Button(root, text = "路径选择", command = selectPath).grid(row = 0, column = 2)

root.mainloop()