php生成年月日下载列表的方法
更新时间:2015年04月24日 14:37:58 作者:不吃皮蛋
这篇文章主要介绍了php生成年月日下载列表的方法,涉及php操作日期的相关技巧,非常具有实用价值,需要的朋友可以参考下
本文实例讲述了php生成年月日下载列表的方法。分享给大家供大家参考。具体实现方法如下:
复制代码 代码如下:
function mdy($mid = "month", $did = "day", $yid = "year", $mval, $dval, $yval)
{
if(empty($mval)) $mval = date("m");
if(empty($dval)) $dval = date("d");
if(empty($yval)) $yval = date("Y");
$months = array(1 => "January", 2 => "February", 3 => "March", 4 => "April", 5 => "May", 6 => "June", 7 => "July", 8 => "August", 9 => "September", 10 => "October", 11 => "November", 12 => "December");
$out = "<select name='$mid' id='$mid'>";
foreach($months as $val => $text)
if($val == $mval) $out .= "<option value='$val' selected>$text</option>";
else $out .= "<option value='$val'>$text</option>";
$out .= "</select> ";
$out .= "<select name='$did' id='$did'>";
for($i = 1; $i <= 31; $i++)
if($i == $dval) $out .= "<option value='$i' selected>$i</option>";
else $out .= "<option value='$i'>$i</option>";
$out .= "</select> ";
$out .= "<select name='$yid' id='$yid'>";
for($i = date("Y"); $i <= date("Y") + 2; $i++)
if($i == $yval) $out.= "<option value='$i' selected>$i</option>";
else $out.= "<option value='$i'>$i</option>";
$out .= "</select>";
return $out;
}
{
if(empty($mval)) $mval = date("m");
if(empty($dval)) $dval = date("d");
if(empty($yval)) $yval = date("Y");
$months = array(1 => "January", 2 => "February", 3 => "March", 4 => "April", 5 => "May", 6 => "June", 7 => "July", 8 => "August", 9 => "September", 10 => "October", 11 => "November", 12 => "December");
$out = "<select name='$mid' id='$mid'>";
foreach($months as $val => $text)
if($val == $mval) $out .= "<option value='$val' selected>$text</option>";
else $out .= "<option value='$val'>$text</option>";
$out .= "</select> ";
$out .= "<select name='$did' id='$did'>";
for($i = 1; $i <= 31; $i++)
if($i == $dval) $out .= "<option value='$i' selected>$i</option>";
else $out .= "<option value='$i'>$i</option>";
$out .= "</select> ";
$out .= "<select name='$yid' id='$yid'>";
for($i = date("Y"); $i <= date("Y") + 2; $i++)
if($i == $yval) $out.= "<option value='$i' selected>$i</option>";
else $out.= "<option value='$i'>$i</option>";
$out .= "</select>";
return $out;
}
希望本文所述对大家的javascript程序设计有所帮助。
相关文章
无法在发生错误时创建会话,请检查 PHP 或网站服务器日志,并正确配置 PHP 安装(win+linux)
今天帮客户配置服务器的时候运行phpmyadmin出现了“无法在发生错误时创建会话,请检查 PHP 或网站服务器日志,并正确配置 PHP 安装。”的错误,经排查原来是权限问题,大家可以参考下面的方法解决2012-05-05
最新评论