如何从一个php文件向另一个地址post数据,不用表单和隐藏的变量的
更新时间:2007年03月06日 00:00:00 作者:
可以使用以下函数来实现:
<?php
function posttohost($url, $data) {
$url = parse_url($url);
if (!$url) return "couldn't parse url";
if (!isset($url['port'])) { $url['port'] = ""; }
if (!isset($url['query'])) { $url['query'] = ""; }
$encoded = "";
while (list($k,$v) = each($data)) {
$encoded .= ($encoded ? "&" : "");
$encoded .= rawurlencode($k)."=".rawurlencode($v);
}
$fp = fsockopen($url['host'], $url['port'] ? $url['port'] : 80);
if (!$fp) return "Failed to open socket to $url[host]";
fputs($fp, sprintf("POST %s%s%s HTTP/1.0\n", $url['path'], $url['query'] ? "?" : "", $url['query']));
fputs($fp, "Host: $url[host]\n");
fputs($fp, "Content-type: application/x-www-form-urlencoded\n");
fputs($fp, "Content-length: " . strlen($encoded) . "\n");
fputs($fp, "Connection: close\n\n");
fputs($fp, "$encoded\n");
$line = fgets($fp,1024);
if (!eregi("^HTTP/1\.. 200", $line)) return;
$results = ""; $inheader = 1;
while(!feof($fp)) {
$line = fgets($fp,1024);
if ($inheader && ($line == "\n" || $line == "\r\n")) {
$inheader = 0;
}
elseif (!$inheader) {
$results .= $line;
}
}
fclose($fp);
return $results;
}
?>
--------------------------------------------------------------------------------------------------
也可以这样
<?php
$URL="www.mysite.com/test.php";
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL,"https://$URL");
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, "Data1=blah&Data2=blah");
curl_exec ($ch);
curl_close ($ch);
?>
相关文章
php输出echo、print、print_r、printf、sprintf、var_dump的区别比较
本篇文章是对php输出echo、print、print_r、printf、sprintf、var_dump的区别进行了详细的分析介绍,需要的朋友参考下2013-06-06
LINUX下PHP程序实现WORD文件转化为PDF文件的方法
这篇文章主要介绍了LINUX下PHP程序实现WORD文件转化为PDF文件的方法,涉及php针对Word文档与pdf格式文件的相关操作技巧,需要的朋友可以参考下2016-05-05


最新评论