Python argv用法详解

#-*- coding:utf- -*-
from sys import argv
script,first = argv
print "the script is called:", script
print "the first variable is:", first 

#-*- coding:utf- -*-
from sys import argv
f = open(argv[], 'r')
print f.read()
f.close() 

import sys,os 
os.system(sys.argv[1]) 

import sys 
def readfile(filename): #从文件中读出文件内容 
'''''Print a file to the standard output.''' 
f = file(filename) 
while True: 
line = f.readline() 
if len(line) == 0: 
break 
print line, # notice comma 分别输出每行内容 
f.close() 
# Script starts from here 
if len(sys.argv) < 2: 
print 'No action specified.' 
sys.exit() 
if sys.argv[1].startswith('--'): 
option = sys.argv[1][2:] 
# fetch sys.argv[1] but without the first two characters 
if option == 'version': #当命令行参数为-- version，显示版本号 
print 'Version 1.2' 
elif option == 'help': #当命令行参数为--help时，显示相关帮助内容 
print '''''/ 
This program prints files to the standard output. 
Any number of files can be specified. 
Options include: 
--version : Prints the version number 
--help : Display this help''' 
else: 
print 'Unknown option.' 
sys.exit() 
else: 
for filename in sys.argv[1:]: #当参数为文件名时，传入readfile，读出其内容 
readfile(filename)