Python中的字符串查找操作方法总结

str = 'a,hello' 
print str.find('hello') # 在字符串str里查找字符串hello 
>> 2     # 输出结果 

target = 'abb aba'
pattern = 'aba'

def match(target, pattern):
  i = j = 0
  n, m = len(target), len(pattern)
  while i < n and j < m:
    # 如果字符相等则目标和模板的下标都向右移
    if target[i] == pattern[j]:
      i, j = i+1, j+1
    else:
      # 如果字符不相等则目标下标切换到不相等的下标
      # 模板下标移动到初始下标
      i = i - j + 1
      j = 0
  if j == m:
    return i - j
  return -1

#修改的地方
else:
  i = i -j + 1
  j = 0
  print(target[i], pattern[j], i, j)

# 打印结果
b a 1 0
b a 2 0
 a 3 0
a a 4 0

def match(target, pattern):
  i = j = 0
  n, m = len(target), len(pattern)
  while i < n and j < m:
    # 如果字符相等则目标和模板的下标都向右移
    if if j == -1 and target[i] == pattern[j]:
      i, j = i+1, j+1
    else:
      # 这里通过next 函数来判断位移个数
      i = i - j + pattern_next(pattern[:j])
      j = 0
  if j == m:
    return i - j
  return -1


def pattern_next(s):  
  prefix = [s[:i+1] for i in range(len(s)-1)]
  suffix = [s[i+1:] for i in range(len(s)-1)]
  l = list(set(prefix) & set(suffix))
  return len(l)