Python遍历目录中的所有文件的方法

os.path.join(d[0],d[1]);

 os.path.join(d[0],d[2]);

result = [os.path.join(dp, f) for dp, dn, fs in os.walk("_pages") for f in fs if os.path.splitext(f)[1] == '.html']
for fname in result:
 #do something

result=[]
for dp, dn, fs in os.walk("_pages"):
 for f in fs:
 if (os.path.splitext(f)[1] == '.html'):
  result.append(os.path.join(dp, f))
for fname in result:
 #do something

result = [y for x in os.walk(PATH) for y in glob.glob(os.path.join(x[0], '*.txt'))]

from itertools import chain
import glob
result = (chain.from_iterable(glob.iglob(os.path.join(x[0], '*.txt')) for x in os.walk('.')))

import os, fnmatch 
 
def filter_files(dirname, patterns='*', single_level=False, yield_folders=False): 
  patterns = patterns.split(';') 
  allfiles = [] 
  for rootdir, subdirname, files in os.walk(dirname): 
    print subdirname 
    allfiles.extend(files) 
    if yield_folders: 
      allfiles.extend(dubdirname) 
    if single_level: 
      break 
  allfiles.sort() 
  for eachpattern in patterns: 
    for eachfile in fnmatch.filter(allfiles, eachpattern): 
        print os.path.normpath(eachfile)