详解Python 数据库 (sqlite3)应用

# By Vamei
import sqlite3

# test.db is a file in the working directory.
conn = sqlite3.connect("test.db")

c = conn.cursor()

# create tables
c.execute('''CREATE TABLE category
   (id int primary key, sort int, name text)''')
c.execute('''CREATE TABLE book
   (id int primary key, 
    sort int, 
    name text, 
    price real, 
    category int,
    FOREIGN KEY (category) REFERENCES category(id))''')

# save the changes
conn.commit()

# close the connection with the database
conn.close()

# By Vamei

import sqlite3

conn = sqlite3.connect("test.db")
c  = conn.cursor()

books = [(1, 1, 'Cook Recipe', 3.12, 1),
      (2, 3, 'Python Intro', 17.5, 2),
      (3, 2, 'OS Intro', 13.6, 2),
      ]

# execute "INSERT" 
c.execute("INSERT INTO category VALUES (1, 1, 'kitchen')")

# using the placeholder
c.execute("INSERT INTO category VALUES (?, ?, ?)", [(2, 2, 'computer')])

# execute multiple commands
c.executemany('INSERT INTO book VALUES (?, ?, ?, ?, ?)', books)

conn.commit()
conn.close()

# By Vamei

import sqlite3

conn = sqlite3.connect('test.db')
c = conn.cursor()

# retrieve one record
c.execute('SELECT name FROM category ORDER BY sort')
print(c.fetchone())
print(c.fetchone())

# retrieve all records as a list
c.execute('SELECT * FROM book WHERE book.category=1')
print(c.fetchall())

# iterate through the records
for row in c.execute('SELECT name, price FROM book ORDER BY sort'):
  print(row)

# By Vamei

conn = sqlite3.connect("test.db")
c = conn.cursor()

c.execute('UPDATE book SET price=? WHERE id=?',(1000, 1))
c.execute('DELETE FROM book WHERE id=2')

conn.commit()
conn.close()

c.execute('DROP TABLE book')