使用js去除字符串内所带有空格的三种方法

var str = " 6 6 ";
var str_1 = str.replace(/\s*/g,"");
console.log(str_1); //66
var str = " 6 6 ";
var str_1 = str.replace(/^\s*|\s*$/g,"");
console.log(str_1); //6 6//输出左右侧均无空格
var str = " 6 6 ";
var str_1 = str.replace(/^\s*/,"");
console.log(str_1); //6 6 //输出右侧有空格左侧无空格
var str = " 6 6 ";
var str_1 = str.replace(/(\s*$)/g,"");
console.log(str_1); // 6 6//输出左侧有空格右侧无空格

var str = " 6 6 ";
var str_1 = str.trim();
console.log(str_1); //6 6//输出左右侧均无空格
单独去除左侧空格则使用 str.trimLeft(); //var str_1 = str.trimLeft();
单独去除右侧空格则使用 str.trimRight();//var str_1 = str.trimRight();

var str = " 6 6 ";
var str_1 = $.trim(str);
console.log(str_1); //6 6//输出左右侧均无空格

var str = '  abc d e f  g ';
        function trim(str) {
            var reg = /[\t\r\f\n\s]*/g;
            if (typeof str === 'string') {
                var trimStr = str.replace(reg,'');
            }
            console.log(trimStr)
        }
        trim(str)

function trimAll(ele){
    if(typeof ele === 'string'){
       return ele.split(/[\t\r\f\n\s]*/g).join('');
    }else{
        console.error(`${typeof ele} is not the expected type, but the string type is expected`)
    }
}
trimAll(str)  // 1234456

function deleSpac(str,direction) { // 1 串的模板 2 清除哪边空格
            if(typeof str !== 'string'){ // 限制下条件，必须是字符串
                 console.error(`${typeof ele} is not the expected type, but the string type is expected`)
                return false
            }
            let Reg = '';
            switch(direction) {
                case 'left' : // 去除左边
                    Reg = /^[\t\r\f\n\s]+/g;
                    break;
                case 'right' : // 去除右边
                    Reg = /([\t\r\f\n\s]+)$/g;
                    break;
                case 'both' : // 去除两边
                    Reg = /(^[\t\r\f\n\s]*)|([\t\r\f\n\s]*$)/g
                    break;
                default :   // 没传默认全部，且为下去除中间空格做铺垫
                    Reg = /[\t\r\f\n\s]*/g;
                    break;
            }
            let newStr = str.replace(Reg,'');
            if ( direction == 'middle' ){
                let RegLeft = str.match(/(^[\t\r\f\n\s]*)/g)[0]; // 保存右边空格
                let RegRight = str.match(/([\t\r\f\n\s]*$)/g)[0]; // 保存左边空格
                newStr = RegLeft + newStr + RegRight; // 将空格加给清完全部空格后的字符串
            }
            return newStr;
        }