JavaScript数字数组的13个实用小技巧

const toDecimal = (num, n = 10) => num.(n) 
// 假设数字10要转换成2进制
toDecimal(10, 2) // '1010'

// 10的2进制为1010
const toDecimalism = (num, n = 10) => parseInt(num, n)
toDecimalism(1010, 2)

const toFixed = (n, fixed) => `${n}`.match(new RegExp(`^-?\d+(?:.\d{0,${fixed}})?`))[0]
toFixed(10.255, 2) // 10.25

const replenishZero = (num, len, zero = 0) => num.().padStart(len, zero)
replenishZero(8, 2) // 08

const formatPhone = (str, sign = '-') => str.replace(/(\W|\s)/g, "").split(/^(\d{3})(\d{4})(\d{4})$/).filter(item => item).join(sign)

formatPhone('13123456789') // '131-2345-6789'
formatPhone('13 1234 56 789', ' ') // '131 2345 6789'

const setTrimOut = str => str.replace(/\s\s+/g, ' ')
const str = setTrimOut('hello,   jack') // 

const createArr = (n) => Array.from(new Array(n), (v, i) => i)
const arr = createArr(100) // 0 - 99 数组

const createArr = (n) => new Array(n).fill(0).map((v, i) => i)
createArr(100) // 0 - 99数组

const randomSort = list => list.sort(() => Math.random() - 0.5)
randomSort([0,1,2,3,4,5,6,7,8,9]) // 随机排列结果

const removeDuplicates = list => [...new Set(list)]
removeDuplicates([0, 0, 2, 4, 5]) // [0,2,4,5]

const intersection = (a, ...arr) => [...new Set(a)].filter((v) => arr.every((b) => b.includes(v)))

intersection([1, 2, 3, 4], [2, 3, 4, 7, 8], [1, 3, 4, 9])
// [3, 4]

const indexOfMax = (arr) => arr.reduce((prev, curr, i, a) => (curr > a[prev] ? i : prev), 0);
indexOfMax([1, 3, 9, 7, 5]); // 2

const indexOfMin = (arr) => arr.reduce((prev, curr, i, a) => (curr < a[prev] ? i : prev), 0)
indexOfMin([2, 5, 3, 4, 1, 0, 9]) // 5

const closest = (arr, n) => arr.reduce((prev, curr) => (Math.abs(curr - n) < Math.abs(prev - n) ? curr : prev))
closest([29, 87, 8, 78, 97, 20, 75, 33, 24, 17], 50) // 33

const zip = (...arr) => Array.from({ length: Math.max(...arr.map((a) => a.length)) }, (_, i) => arr.map((a) => a[i]))
zip([1,2,3,4], ['a', 'b', 'c', 'd'], ['A', 'B', 'C', 'D'])
// [[1, 'a', 'A'], [2, 'b', 'B'], [3, 'c', 'C'], [4, 'd', 'D']]

const transpose = (matrix) => matrix[0].map((col, i) => matrix.map((row) => row[i]));
transpose(
    [              // [
        [1, 2, 3], //      [1, 4, 7],
        [4, 5, 6], //      [2, 5, 8],
        [7, 8, 9], //      [3, 6, 9],
     ]             //  ]
 );