JS将json字符串转换为JsonObject的多种实现方法

let jsonString = '{"name": "John", "age": 30, "city": "New York"}';
let jsonObject = JSON.parse(jsonString);
console.log(jsonObject.name); // 输出: John

try {
    let invalidJsonString = '{"name": "John", "age": 30, "city": "New York"'; // 缺少右括号
    let jsonObject = JSON.parse(invalidJsonString);
} catch (error) {
    console.error("Failed to parse JSON string:", error.message);
}

let jsonString = '{"name": "John", "birthYear": 1992}';
let jsonObject = JSON.parse(jsonString, (key, value) => {
    if (key === 'birthYear') return new Date().getFullYear() - value; // 计算年龄
    return value;
});
console.log(jsonObject.age); // 输出当前年份减去1992

fetch('/api/data')
    .then(response => response.json()) // 自动调用JSON.parse()
    .then(data => console.log(data))
    .catch(error => console.error('Error fetching data:', error));

// 存储数据
let settings = {theme: "dark", fontSize: 16};
localStorage.setItem('userSettings', JSON.stringify(settings));

// 读取数据
let savedSettings = JSON.parse(localStorage.getItem('userSettings'));
console.log(savedSettings.theme); // 输出: dark