详解Go语言如何高效解压ZIP文件

package utils

import (
	"archive/zip"
	"fmt"
	"io"
	"os"
	"path/filepath"
	"strings"
)

// Unzip 解压 ZIP 文件到指定目录
func Unzip(zipFile string, destDir string) ([]string, error) {
	zipReader, err := zip.OpenReader(zipFile)
	var paths []string
	if err != nil {
		return []string{}, err
	}
	defer zipReader.Close()

	for _, f := range zipReader.File {
		if strings.Index(f.Name, "..") > -1 {
			return []string{}, fmt.Errorf("%s 文件名不合法", f.Name)
		}
		fpath := filepath.Join(destDir, f.Name)
		paths = append(paths, fpath)
		if f.FileInfo().IsDir() {
			os.MkdirAll(fpath, os.ModePerm)
		} else {
			if err = os.MkdirAll(filepath.Dir(fpath), os.ModePerm); err != nil {
				return []string{}, err
			}

			inFile, err := f.Open()
			if err != nil {
				return []string{}, err
			}
			defer inFile.Close()

			outFile, err := os.OpenFile(fpath, os.O_WRONLY|os.O_CREATE|os.O_TRUNC, f.Mode())
			if err != nil {
				return []string{}, err
			}
			defer outFile.Close()

			_, err = io.Copy(outFile, inFile)
			if err != nil {
				return []string{}, err
			}
		}
	}
	return paths, nil
}

package main

import (
	"fmt"
	"log"
	"utils"
)

func main() {
	zipFile := "example.zip"  // 需要解压的 ZIP 文件
	destDir := "output"        // 解压目标目录

	files, err := utils.Unzip(zipFile, destDir)
	if err != nil {
		log.Fatalf("解压失败: %v", err)
	}

	fmt.Println("解压成功，文件列表:")
	for _, file := range files {
		fmt.Println(file)
	}
}