go语言rejson读取后Unmarshal乱码的解决过程

obj := map[string]interface{}{
		"t1": "你好2Af1不行.a",
		"t2": "你好",
	}

{"t1":"\u00e4\u00bd\u00a0\u00e5\u00a5\u00bd2Af1\u00e4\u00b8\u008d\u00e8\u00a1\u008c.a","t2":"\u00e4\u00bd\u00a0\u00e5\u00a5\u00bd"}

map[t1:ä½ å¥½2Af1不行.a t2:ä½ å¥½]

func Test() {
	// 测试代码
	rh := rejson.NewReJSONHandler()
	client := redis.NewClient(&redis.Options{
		Addr:     "192.168.1.131:6379", // use default Addr
		Password: "",                   // no password set
		DB:       0,                    // use default DB
	})
	_, err := client.Ping().Result()
	if err != nil {
		return
	}
	rh.SetGoRedisClient(client)
	key := "TEST"
	path := "."
	obj := map[string]interface{}{
		"t1": "你好2Af1不行.a",
		"t2": "你好",
	}
	fmt.Printf("%s\n", obj)
	res, err := rh.JSONSet(key, path, obj)
	if err != nil {
		return
	}
	fmt.Println(res)
	resJson, err := rh.JSONGet(key, path)
	if err != nil {
		return
	}
	fmt.Printf("%s\n", resJson)
	obj2 := map[string]interface{}{}
	err = json.Unmarshal(resJson.([]uint8), &obj2)
	fmt.Printf("%s\n", obj2)
	// 加上\u00xx转换为二进制
	js2, err := RejsonDecodeu00xx(resJson.([]uint8))
	if err != nil {
		return
	}
	fmt.Printf("%s\n", js2)
	obj3 := map[string]interface{}{}
	err = json.Unmarshal(js2, &obj3)
	if err != nil {
		return
	}
	fmt.Printf("%s\n", obj3)
	return
}
// TODO: magic func
// 解决rejson存utf8只管存储，不管取的问题
// rejson存储时遇到utf8格式的值，会直接以\u00加上十六进制字符串存储
// rejson.go模块读取时没有做相应的转换。
// 此时调用json.Unmarshal转换为对象时utf8文本会乱码
// 临时方案
func RejsonDecodeu00xx(str []byte) (res []byte, err error) {
	l := len(str)
	for i := 0; i < l; {
		if '\\' == str[i] && i+6 <= l &&
			'u' == str[i+1] && '0' == str[i+2] && '0' == str[i+3] {
			//tmp := string(str[i])
			a, o := unhex(str[i+4])
			if !o {
				err = errors.New("error !")
				return []byte{}, err
			}
			b, o := unhex(str[i+5])
			if !o {
				err = errors.New("error !")
				return []byte{}, err
			}
			c := a*16 + b
			res = append(res, c)
			i += 6
		} else {
			res = append(res, str[i])
			i++
		}
	}
	return res, err
}
func unhex(b uint8) (v uint8, ok bool) {
	c := b
	switch {
	case '0' <= c && c <= '9':
		return c - '0', true
	case 'a' <= c && c <= 'f':
		return c - 'a' + 10, true
	case 'A' <= c && c <= 'F':
		return c - 'A' + 10, true
	}
	return
}