一起解密Python中的*args和**kwargs无限可能的函数参数

def sum_numbers(*args):
    total = 0
    for num in args:
        total += num
    return total
print(sum_numbers(1, 2, 3, 4, 5))  # 输出：15
print(sum_numbers(10, 20, 30))  # 输出：60

def print_person_info(**kwargs):
    for key, value in kwargs.items():
        print(f"{key}: {value}")
print_person_info(name="Alice", age=25, country="USA")
# 输出：
# name: Alice
# age: 25
# country: USA
print_person_info(name="Bob", occupation="Engineer")
# 输出：
# name: Bob
# occupation: Engineer

def process_data(*args, **kwargs):
    for arg in args:
        print(f"Positional argument: {arg}")
    for key, value in kwargs.items():
        print(f"Keyword argument: {key} = {value}")
process_data(1, 2, 3, name="Alice", age=25)
# 输出：
# Positional argument: 1
# Positional argument: 2
# Positional argument: 3
# Keyword argument: name = Alice
# Keyword argument: age = 25

def concatenate_strings(*args):
    return " ".join(args)
result = concatenate_strings("Hello", "world", "!")
print(result)  # 输出：Hello world !

def process_config(**kwargs):
    for key, value in kwargs.items():
        # 在这里处理配置参数
        pass
config = {
    "debug": True,
    "log_file": "app.log",
    "max_connections": 100
}
process_config(**config)

def log_args_and_kwargs(func):
    def wrapper(*args, **kwargs):
        print("Arguments:", args)
        print("Keyword arguments:", kwargs)
        return func(*args, **kwargs)
    return wrapper
@log_args_and_kwargs
def calculate_sum(a, b):
    return a + b
result = calculate_sum(3, 5)
print(result)  # 输出：8