Python中reduce()函数的用法详细解读

def reduce(function, sequence, initial=None): # real signature unknown; restored from __doc__
    """
    reduce(function, sequence[, initial]) -> value
    Apply a function of two arguments cumulatively to the items of a sequence,
    from left to right, so as to reduce the sequence to a single value.
    For example, reduce(lambda x, y: x+y, [1, 2, 3, 4, 5]) calculates
    ((((1+2)+3)+4)+5).  If initial is present, it is placed before the items
    of the sequence in the calculation, and serves as a default when the
    sequence is empty.
    """
    pass

import functools
list1 = [1, 2, 3, 4, 5]
#  方法一
def func(a, b):
    return a + b
result = functools.reduce(func, list1)
print(result)  # 15
# 方法二
result2 = functools.reduce(lambda x, y: x + y, list1)
print(result2)

import functools
list1 = [1, 2, 3, 4, 5]
#  方法一
def func(a, b):
    return a * b
result = functools.reduce(func, list1)
print(result)  # 15
# 方法二
result2 = functools.reduce(lambda x, y: x * y, list1)
print(result2)

import functools
list1 = [1, 2, 3, 4, 5]
list2 = [1, 1, 1, 1, 1]
list3 = [0, 0, 0, 0, 0]
list4 = [0, 0, 0, 0, 1]
result1 = functools.reduce(lambda x, y: x & y, list1)
result2 = functools.reduce(lambda x, y: x & y, list2)
result3 = functools.reduce(lambda x, y: x | y, list3)
result4 = functools.reduce(lambda x, y: x | y, list4)
print(result1)
print(result2)
print(result3)
print(result4)

from functools import reduce
def add(x, y):
    return x + y
a = [1, 2, 3, 4, 5]
#  reduce()两个参数
ret1 = reduce(add, a)
print(ret1)
#  reduce()三个参数
ret2 = reduce(add, a, 6)
print(ret2)

from functools import reduce
from mongoengine import Q
from mongoengine.queryset.visitor import Q
from elasticsearch_dsl import Q as EQ
# query_list = ['x', 'y', 'z']  # 字符串报错：TypeError: unsupported operand type(s) for &: 'str' and 'str'
# query_list = [2, 3]  # 2
# query_list = [2, 3, 4]  # 0
# mongo中使用
query_list = [Q(aa="aa"), Q(bb='bb'), Q(cc='cc'), Q(dd='dd')]  # (Q(**{'aa': 'aa'}) & Q(**{'bb': 'bb'}) & Q(**{'cc': 'cc'}) & Q(**{'dd': 'dd'}))
res = reduce(lambda x, y: x & y, query_list)
print(res)
# es中使用
query_list = [EQ(aa="aa"), EQ(bb='bb'), EQ(cc='cc'), EQ(dd='dd')]  # MatchAll(dd='dd')
res = reduce(lambda x, y: x & y, query_list)
print(res)