Python如何从列表中删除相邻和不相邻的相同元素

结果：list=[1,2,3,4]
#第一种
list = [1,2,3,3,4,1,1]
new_list = []
for i in list[:]:
    if i not in new_list:  #可以删除重复元素，不管是否相邻
        new_list.append(i)
print(new_list)
# 第二种  集合可以去重  先转换成集合再转换成列表
list = [1,2,3,3,4,1,1]
print(list(set(list)))
# 第三种
list = [1,2,3,3,4,1,1]
list.sort()
new_list = []
for i in range(len(list) - 1):
    if list[i] == list[i + 1]:
        new_list.append(list[i + 1])
for j in new_list:
    list.remove(j)
print(list)
# 第四种
# fromkeys 是把所有的键都赋同样的值（如果不指定内容则默认赋值为None）
list = [1,2,3,3,4,1,1]
new_list = []
dct = dict.fromkeys(list)
# print(dct)
for n in dct:
    new_list.append(n)
print(new_list)
# 第五种  第四种方法的简写
list1 = [1,2,3,3,4,1,1]
print(list(dict.fromkeys(list1)))

#结果：list1 = [1, 2, 3, 4, 1]
#第一种，比较相邻两个值，若相同，则del其中一个，逐个遍历，直到没有重复的。
list1 = [1,2,2,3,3,4,1,1]
for i in range(len(list1) - 1, 0, -1):
    if list1[i] == list1[i-1]:
        del list1[i]
print(list1)
#第二种，使用itertools库
import itertools
list1 = [1,2,2,3,3,4,1,1]
new_list1 = [k for k, g in itertools.groupby(list1)]
print(new_list1)
#第三种 生成器(generator)
#其中del_adjacent()是一个生成器类型，需要使用list转换成列表
list1 = [1,2,2,3,3,4,1,1]
def del_adjacent(iterable):
 prev = object()
 for iterm in iterable:
     if iterm != prev:
         prev = iterm
         yield iterm
a = list(del_adjacent(list1))
print(a)

In [1]: import itertools
In [2]: a=[0, 1, 3, 2, 4, 4, 5, 6, 7, 8, 10, 11, 12, 13, 14, 16, 16, 17, 18, 18, 19, 20, 20, 21, 22, 22, 22, 23, 23, 23, 26, 29, 29, 30, 32, 33, 34, 32, 32, 15, 24]
In [3]: b=[k for k, _ in itertools.groupby(a)]
In [4]: print(b)
[0, 1, 3, 2, 4, 5, 6, 7, 8, 10, 11, 12, 13, 14, 16, 17, 18, 19, 20, 21, 22, 23, 26, 29, 30, 32, 33, 34, 32, 15, 24]

In [22]: import numpy as np
In [23]: a=[0, 1, 3, 2, 4, 4, 5, 6, 7, 8, 10, 11, 12, 13, 14, 16, 16, 17, 18, 18, 19, 20, 20, 21, 22, 22, 22, 23, 23, 23, 26, 29, 29, 30, 32, 33, 34, 32, 32, 15, 24]
In [24]: m=a[1:]
In [25]: n=a[:-1]
In [26]: len(a)
Out[26]: 41
In [27]: len(m)
Out[27]: 40
In [28]: len(n)
Out[28]: 40
In [29]: c=[i[0]==i[1] for i in zip(m, n)]
In [30]: print(c)
[False, False, False, False, True, False, False, False, False, False, False, False, False, False, False, True, False, False, True, False, False, True, False, False, True, True, False, True, True, False, False, True, False, False, False, False, False, True, False, False]
In [31]: d=np.array(a[:-1])[c]
In [32]: print(d)
[ 4 16 18 20 22 22 23 23 29 32]
In [33]: result = list(set(d))
In [34]: result
Out[34]: [32, 4, 16, 18, 20, 22, 23, 29]

In [35]: import operator
In [36]: import itertools
In [37]: c2=list(map(operator.eq, a, itertools.islice(a, 1, None)))
In [38]: print(c2)
[False, False, False, False, True, False, False, False, False, False, False, False, False, False, False, True, False, False, True, False, False, True, False, False, True, True, False, True, True, False, False, True, False, False, False, False, False, True, False, False]
In [39]: c==c2
Out[39]: True