基于python实现弱密码检测工具

import crypt
import commands
import sys

def testPass(user,cryptPass,ipaddr):
    #dictfile=open('dictionary.txt','r')
    start_index=cryptPass.find("$")
    finish_index=cryptPass.rfind("$")
    salt=cryptPass[start_index:finish_index+1]
    dictfile=open('/root/dict.txt','r')
    pwd_suffix = ['','.','..','!','!@#','1','123','1234','12345','123456','888','666','999','2006','2007','2008','2009','2010','2011','2012','2013','2014','2015','2016','2017','2018','2019']
    for sfx in pwd_suffix:
        #print user+sfx
        for separator in ['','@','#','&']:
            cryptWord=crypt.crypt('%s%s%s'%(user,separator,sfx),salt)
            if cryptWord==cryptPass:
                #print ipaddr + " [+] Found Password: " +user+'/'+user+sfx+ " \n"
                print '%s [+] Found Passwd: %s/%s%s%s \n'%(ipaddr,user,user,separator,sfx)
                break
            cryptWord=crypt.crypt('%s%s%s'%(user,sfx,separator),salt)
            if cryptWord==cryptPass:
                #print ipaddr + " [+] Found Password: " +user+'/'+user+sfx+ " \n"
                print '%s [+] Found Passwd: %s/%s%s%s \n'%(ipaddr,user,user,sfx,separator)
                break
    for word in dictfile.readlines():
        #print word
        word=word.strip()
        cryptWord=crypt.crypt(word,salt)
        if cryptWord==cryptPass:
            print ipaddr + " [+] Found Password: " +user+'/'+word+ " \n"
            break
    print('[-] Password not found!')

def main():
    cmd = "ifconfig|grep \"inet addr\"|grep -v 127.0.0.1|awk '{print $2}'"
    ipaddr = commands.getoutput(cmd).replace('addr:','').replace('\n','|')
    shadowfile=open('/etc/shadow')
    for line in shadowfile.readlines():
        user=line.split(':')[0]
        cryptPass=line.split(':')[1].strip('\n')
        if not (cryptPass.startswith('*') or cryptPass.startswith('!')): 
            print "[*] Cracking Password For: " +user
            testPass(user,cryptPass,ipaddr)

if __name__=='__main__':
    main()