Python中惊艳的一行代码简洁强大表达力技巧实例

# 示例1：生成1到10的平方列表
squares = [x**2 for x in range(1, 11)]

# 示例2：筛选出列表中的偶数
even_numbers = [x for x in range(1, 11) if x % 2 == 0]

# 示例3：字母转为大写并去除空格
words = ["hello", "world", "python"]
upper_words = [word.upper().strip() for word in words]

# 示例1：计算平方
square = lambda x: x**2

# 示例2：检查是否为偶数
is_even = lambda x: x % 2 == 0

# 示例3：合并两个字符串
concatenate = lambda a, b: a + b

# 示例1：将列表中的每个元素平方
squares = list(map(lambda x: x**2, [1, 2, 3, 4, 5]))

# 示例2：过滤出列表中的偶数
even_numbers = list(filter(lambda x: x % 2 == 0, [1, 2, 3, 4, 5]))

# 示例3：计算所有元素的平均值
average = sum([1, 2, 3, 4, 5]) / len([1, 2, 3, 4, 5])

# 示例1：判断奇偶性
result = "even" if 6 % 2 == 0 else "odd"

# 示例2：将数字转为正数
absolute_value = lambda x: x if x >= 0 else -x

# 示例1：读取文件所有行
lines = [line.strip() for line in open("example.txt")]

# 示例2：写入文件
with open("output.txt", "w") as f:
    f.write("Hello, World!")

# 示例1：将两个列表合并为字典
keys = ["name", "age", "city"]
values = ["Alice", 25, "New York"]
person_dict = dict(zip(keys, values))

# 示例2：获取列表元素及其索引
fruits = ["apple", "banana", "cherry"]
for index, fruit in enumerate(fruits):
    print(f"Index: {index}, Fruit: {fruit}")

# 示例1：将列表元素作为键，平方作为值构建字典
squares_dict = {x: x**2 for x in range(1, 6)}

# 示例2：筛选出字典中值大于10的项
original_dict = {"a": 5, "b": 12, "c": 8}
filtered_dict = {key: value for key, value in original_dict.items() if value > 10}

# 示例1：生成斐波那契数列
fibonacci = (x if x <= 1 else fibonacci[x-1] + fibonacci[x-2] for x in range(10))

# 示例2：生成器表达式与条件判断
even_squares = (x**2 for x in range(10) if x % 2 == 0)

# 示例1：计时器装饰器
import time

def timer(func):
    def wrapper(*args, **kwargs):
        start_time = time.time()
        result = func(*args, **kwargs)
        end_time = time.time()
        print(f"{func.__name__}运行时间：{end_time - start_time}秒")
        return result
    return wrapper

# 示例2：使用计时器装饰器
@timer
def slow_function():
    time.sleep(2)
    print("Function executed")

# 调用装饰后的函数
slow_function()

# 示例：使用三引号创建多行字符串
multi_line_string = """
这是一个
多行字符串
示例。
"""

# 示例：FizzBuzz问题的一行代码解决方案
print("\n".join("Fizz"*(i%3==0) + "Buzz"*(i%5==0) or str(i) for i in range(1, 101)))