详解Python如何检查一个数字是否为科技数

def is_tech_number(num):
    square = num ** 2
    square_str = str(square)
    length = len(square_str)
    for i in range(1, length):
        front_half = int(square_str[:i])
        back_half = int(square_str[i:])
        if front_half + back_half == num:
            return True
    return False

# 检测数字是否是科技数
print(is_tech_number(3025))  # 输出：True
print(is_tech_number(2025))  # 输出：False

def play_tech_number_game():
    num = int(input("请输入一个数字："))
    if is_tech_number(num):
        print(f"恭喜，{num}是一个科技数！你赢了！")
    else:
        print(f"抱歉，{num}不是一个科技数。你输了。")

play_tech_number_game()

def process_numbers(numbers):
    tech_numbers = [num for num in numbers if is_tech_number(num)]
    print("科技数列表：", tech_numbers)

numbers = [i for i in range(1, 101)]
process_numbers(numbers)

import time

def calculate_tech_numbers(start, end):
    tech_numbers = []
    for num in range(start, end+1):
        if is_tech_number(num):
            tech_numbers.append(num)
    return tech_numbers

start_time = time.time()
result = calculate_tech_numbers(1, 10000)
end_time = time.time()
print("计算时间：", end_time - start_time)
print("科技数列表：", result)

class TechNumberSet:
    def __init__(self):
        self.tech_numbers = set()

    def add(self, num):
        if is_tech_number(num):
            self.tech_numbers.add(num)

    def get_tech_numbers(self):
        return self.tech_numbers

tech_set = TechNumberSet()
for i in range(1, 1001):
    tech_set.add(i)
print("科技数集合：", tech_set.get_tech_numbers())