Python实现解析路径字符串并获取每个文件夹名称

import os

path = "/home/user/Documents/example.txt"
dirname, filename = os.path.split(path)

print("目录部分：", dirname)
print("文件名部分：", filename)

import os

def get_folder_names(path):
    folders = []
    while True:
        path, folder = os.path.split(path)
        if folder:
            folders.append(folder)
        else:
            if path:
                folders.append(path)
            break
    return list(reversed(folders))

path = "/home/user/Documents/example.txt"
folder_names = get_folder_names(path)

​​​​​​​print("每个文件夹的名称：", folder_names)

import os

def list_folders(path):
    folders = []
    for root, dirs, files in os.walk(path):
        for folder in dirs:
            folders.append(folder)
    return folders

# 示例：遍历当前目录下的文件夹并打印它们的名称
current_path = os.getcwd()
folders = list_folders(current_path)
print("当前目录下的文件夹：", folders)

from urllib.parse import urlparse

def parse_url(url):
    parsed_url = urlparse(url)
    return parsed_url.path.split('/')

​​​​​​​# 示例：解析URL并获取路径部分的名称
url = "https://www.example.com/path/to/resource"
path_parts = parse_url(url)
print("URL路径部分的名称：", path_parts)

def extract_folder_names(file_path):
    folders = file_path.split('/')
    return [folder for folder in folders if folder]

# 示例：解析文件路径并获取每个文件夹的名称
file_path = "/path/to/directory/file.txt"
folder_names = extract_folder_names(file_path)
print("文件路径中的文件夹名称：", folder_names)