Python脚本启动应用并输入账号或密码的操作命令

import pyautogui
import keyring
import time
import subprocess
import sys
import psutil
import os
def run_application_with_account(application_path, account):
    # 设置密码到系统的安全存储中
    keyring.set_password("example_application", "user", account)
    # 启动应用程序
    subprocess.Popen(application_path)
    # 等待一段时间，确保应用程序已完全加载
    time.sleep(5)
    # 使用pyautogui模拟键盘输入账号
    pyautogui.write(account)
    pyautogui.press('enter')
def f_exeIsRunning(exe_path):
    # function:  判断exe可执行文件是否正在运行
    #       in:  exe_path：exe可执行文件的路径
    #      out:  bool
    #   return:  True or False
    #   others:  Determines If The EXE Is Running Func
    for proc in psutil.process_iter(['name']):
        try:
            if proc.info['name'] == os.path.basename(exe_path):
                return True
        except (psutil.NoSuchProcess, psutil.AccessDenied, psutil.ZombieProcess):
            return False
if __name__ == "__main__":
    application_path = "D:\Programs\OrdinaryApps\Tencent\QQ\Bin\QQScLauncher.exe"
    if f_exeIsRunning(application_path):
        # 如果已经打开，打印路径
        print(f"{application_path} 已经打开")
        sys.exit(0)
    else:
        # 如果未打开，则打开
        print(f"{application_path} 未打开")
        password = keyring.get_password("example_application", "user")
        if not password:
            password = "895860"
            # password = input("请输入密码:")
        #打开应用并输入密码或者账号，并模拟enter健登录
        try:
            run_application_with_account(application_path, password)
        except Exception as e:
            print("发生错误:", e)
 

python D:\Workspace\Python\StartAPP\startQQ.py

python startQQ.py