Python 超时请求或计算的处理方案

response = requests.post(url, 
						data=request_body, 
						headers=headers, 
						timeout=timeout)

import signal
from functools import wraps
import errno
import os
class TimeoutError(Exception):
    pass
def timeout(seconds=10, error_message=os.strerror(errno.ETIME)):
    def decorator(func):
        def _handle_timeout(signum, frame):
            raise TimeoutError(error_message)
        def wrapper(*args, **kwargs):
            signal.signal(signal.SIGALRM, _handle_timeout)
            signal.alarm(seconds)
            try:
                result = func(*args, **kwargs)
            finally:
                signal.alarm(0)
            return result
        return wraps(func)(wrapper)
    return decorator
@timeout(5)
def long_running_function():
    # 这里是可能会长时间运行的代码
    # 例如，可以使用 time.sleep 来模拟长时间运行的操作
    import time
    time.sleep(10)
try:
    long_running_function()
except TimeoutError as e:
    print("Function call timed out")